A plot of 1/V vs. 1/[S] for an enzyme catalyzed reaction gave a line with an equation of y = 0.5x + 0.2. The same enzyme with an inhibitor present gave a line with an equation of y = 1.1x + 0.2. Which of the following statements is true? A) the type of inhibition is competitive B) the type of inhibition is noncompetitive C) the type of inhibition is uncompetitive D) the V_max with the inhibitor present has decreased E) the K_m with the inhibitor present has decreased

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Quizplus · Accepted Answer

The plot described is a Lineweaver-Burk plot, which is used to analyze enzyme kinetics. In the case of competitive inhibition, the slope of the line (1/Vmax) changes, but the y-intercept (1/Km) remains the same. The given equations show that with the inhibitor, the slope (1.1x) is different from without the inhibitor (0.5x), but the y-intercept (0.2) remains unchanged, indicating competitive inhibition.

A Plot of 1/V Vs