The equilibrium constants for the two reactions are known: M^m+ + 4 L^- $\leftrightarrows$ [ML₄]^m^-⁴ K_f
HL $\leftrightarrows$ H⁺ + L^- K_a
What is the equilibrium constant,K_overall,for the reaction,M^m+ + 4 HL $\leftrightarrows$ [ML₄]^m^-⁴ + 4 H⁺?

Question

The equilibrium constants for the two reactions are known: M^m+ + 4 L^-

\leftrightarrows

[ML₄]^m^-⁴ K_f
HL

\leftrightarrows

H⁺ + L^- K_a
What is the equilibrium constant,K_overall,for the reaction,M^m+ + 4 HL

\leftrightarrows

[ML₄]^m^-⁴ + 4 H⁺?

Quizplus · Accepted Answer

The equilibrium constant for the overall reaction can be obtained by multiplying the equilibrium constants of the individual reactions involved in the process. Therefore, K_overall = K_f × K_a × (^-)⁴/(H⁺)⁴ Note that the stoichiometric coefficient of H^and in the overall reaction is 4, so their concentrations in the equilibrium expression are raised to the power of 4. Therefore, the correct answer is D, which is K_f × K_a × (^-)⁴/(H⁺)⁴.

The Equilibrium Constants for the Two Reactions Are Known: Mm+ ⇆\leftrightarrows⇆

The Equilibrium Constants for the Two Reactions Are Known: M^m+ $\leftrightarrows$