For the equilibrium 2 NOBr(g)$\leftrightarrows$ 2 NO(g)+ Br₂(g),K_c = 1.56 $\times$ 10^-3 at 300.0 K.What is K_p at 300.0 K for the equilibrium,NO(g)+ Br₂(g)$\leftrightarrows$ NOBr(g)?

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The Answer of For the equilibrium 2 NOBr(g)$\leftrightarrows$ 2 NO(g)+ Br₂(g),K_c = 1.56 $\times$ 10^-3 at 300.0 K.What is K_p at 300.0 K for the equilibrium,NO(g)+ Br₂(g)$\leftrightarrows$ NOBr(g)?

For the Equilibrium 2 NOBr(g) ⇆\leftrightarrows⇆ 2 NO(g)+ Br2(g),Kc = 1 ×\times×

For the Equilibrium 2 NOBr(g) $\leftrightarrows$ 2 NO(g)+ Br₂(g),K_c = 1 $\times$