The Rate Constant for the First-Order Decomposition of a Particular $\times$

The rate constant for the first-order decomposition of a particular hydrocarbon is 1.85 $\times$ 10^-6 s^-1 at 485 K.If the activation energy is 84.0 kJ/mol,what is the value of the frequency factor at this temperature?

A) 4.85 $\times$ 10^-4 s^-1
B) 1.11 $\times$ 10⁹ s^-1
C) 2.2 $\times$ 10¹ s^-1
D) 2.06 $\times$ 10³ s^-1
E) 1.81 $\times$ 10^-6 s^-1