Determine $\Delta$S $\circ$ for the reaction,Zn(s)+ 2 HCl(aq)$\leftrightarrows$ ZnCl₂(aq)+ H₂(g),given

Question

Quizplus · Accepted Answer

The change in entropy (ΔS°) for the reaction can be calculated using the standard molar entropies of the reactants and products. ΔS° = [S°(ZnCl₂(aq)) + S°(H₂(g))] - [S°(Zn(s)) + 2*S°(HCl(aq))]. Since ZnCl₂(aq) is composed of Zn²⁺ and 2Cl⁻, its entropy is S°(Zn²⁺) + 2*S°(Cl⁻). Plugging in the values: ΔS° = [(-106.5 + 2*55.10) + 130.58] - [60.9 + 2*56.5] = -39.6 J/K.

Determine Δ\DeltaΔ S ∘\circ∘ for the Reaction,Zn(s)+ 2 HCl(aq) ⇆\leftrightarrows⇆ ZnCl2(aq)+ H2(g),given A)0 J/K B)-39

Determine $\Delta$ S^$\circ$ for the Reaction,Zn(s)+ 2 HCl(aq) $\leftrightarrows$ ZnCl₂(aq)+ H₂(g),given

A)0 J/K
B)-39