How much heat is liberated at constant pressure when 2.35 g of potassium metal reacts with 5.68 mL of liquid iodine monochloride (d = 3.24 g/mL) ? 2K(s) + ICl(l) KCl(s) + KI(s)
H° = -740.71 kJ/mol
A) 2.22 103 kJ
B) 8.40 101 kJ
C) 1.28 102 kJ
D) 2.23 101 kJ
E) 7.41 102 kJ
Correct Answer:
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