A 7.11-g sample of potassium chlorate was decomposed according to the following equation: 2KClO₃ $\to$ 2KCl + 3O₂
How many moles of oxygen are formed?

Question

A 7.11-g sample of potassium chlorate was decomposed according to the following equation: 2KClO₃

\to

2KCl + 3O₂
How many moles of oxygen are formed?

Quizplus · Accepted Answer

The Answer of A 7.11-g sample of potassium chlorate was decomposed according to the following equation: 2KClO₃ $\to$ 2KCl + 3O₂ How many moles of oxygen are formed? A)2.78 g B)0.0580 mol C)0.0387 mol D)0.0870 mol E)none of these

A 711-G Sample of Potassium Chlorate Was Decomposed According to the the Following