Consider the following reaction: What mass of CCl₄ is formed by the reaction of 5.14 g of methane with an excess of chlorine? A)12.3 g B)0.54 g C)791 g D)49.3 g E)none of these

Question

Quizplus · Accepted Answer

The balanced equation for the reaction is:

CH4 + 4Cl2 → CCl4 + 4HCl

From the equation, we can see that 1 mole of methane (16 g) reacts with 4 moles of chlorine (4 x 71 g = 284 g) to form 1 mole of CCl4 (154 g).

So, to find the mass of CCl4 formed from 5.14 g of CH4, we can use the following proportion:

(1 mole CH4 / 16 g) × (1 mole CCl4 / 1 mole CH4) × (154 g / 1 mole CCl4) × (5.14 g CH4 / 1) = 49.3 g CCl4

Therefore, the answer is D) 49.3 g.

Consider the Following Reaction: What Mass of CCl4 Is

Consider the Following Reaction: What Mass of CCl₄ Is