The galvanic cell described by Zn(s)| Zn²⁺(aq)| Cu²⁺(aq)| Cu(s)has a standard cell potential of 1.101 volts.Given that Zn(s)$\to$Zn²⁺(aq)+ 2e^- has an oxidation potential of 0.764 volts,determine the reduction potential for .

Question

Quizplus · Accepted Answer

The cell potential is given by the difference between the reduction potential of the cathode (Cu2+ + 2e- → Cu) and the oxidation potential of the anode (Zn → Zn2+ + 2e-).

We know that the standard cell potential is 1.101 V, and the oxidation potential of the anode (Zn) is 0.764 V. Therefore, the reduction potential of the cathode (Cu2+ + 2e- → Cu) can be found by subtracting the oxidation potential from the standard cell potential: 
Reduction potential = Standard cell potential - Oxidation potential
Reduction potential = 1.101 V - 0.764 V
Reduction potential = 0.337 V

Therefore, the correct answer is (D) 0.337 V.

The Galvanic Cell Described by Zn(s)| Zn2+(aq)| Cu2+(aq)| Cu(s)has a Standard

The Galvanic Cell Described by Zn(s)| Zn²⁺(aq)| Cu²⁺(aq)| Cu(s)has a Standard