For the process CHCl₃(s) $\to$CHCl₃(l),$\Delta$H° = 9.19 kJ/mol and $\Delta$S° = 43.9 J/mol/K.What is the melting point of chloroform?

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Quizplus · Accepted Answer

The melting point of chloroform can be calculated using the Gibbs free energy change and the entropy change:$$\Delta G = \Delta H - T\Delta S$$At the melting point, $\Delta G = 0$, so:$$T = \frac{\Delta H}{\Delta S}$$Substituting the given values:$$T = \frac{9.19 kJ/mol}{43.9 J/mol/K} = 209 K$$Converting to Celsius:$$T = 209 K - 273.15 = -64 °C$$Therefore, the melting point of chloroform is -64 °C.

For the Process CHCl3(s) →\to→ CHCl3(l) Δ\DeltaΔ H° = 919 KJ/mol And CHCl3(s)

For the Process CHCl₃(s) $\to$ CHCl₃(l) $\Delta$ H° = 919 KJ/mol And CHCl₃(s)