Given That $\Delta$ G_f° for NH₃ = -16 $\times$ 10⁵
B)8 $\times$ 10²
C)1

Given that $\Delta$ G_f° for NH₃ = -16.668 kJ/mol,calculate the equilibrium constant for the following reaction at 298 K: N₂(g) + 3H₂(g) 2NH₃(g)

A) 6.97 $\times$ 10⁵
B) 8.35 $\times$ 10²
C) 1.01
D) 4.51 $\times$ 10⁶⁹
E) 5.82 $\times$ 10⁸