The equilibrium constant K for the dissociation reaction of a molecule X₂ X₂(g) 2X(g) Was measured as a function of temperature (in K).A graph of ln Kversus 1/T for this reaction gives a straight line with a slope of -1.352 $\times$ 10⁴and an intercept of 15.59 K.The value of $\Delta$S for this dissociation reaction is:

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The Answer of The equilibrium constant K for the dissociation reaction of a molecule X₂ X₂(g) 2X(g) Was measured as a function of temperature (in K).A graph of ln Kversus 1/T for this reaction gives a straight line with a slope of -1.352 $\times$ 10⁴and an intercept of 15.59 K.The value of $\Delta$S for this dissociation reaction is:

The Equilibrium Constant K for the Dissociation Reaction of a Molecule