Determine the equilibrium concentration of the chloride ion. A)3.9 $\times$ 10^-⁴ B)8.0 $\times$ 10^-⁶ C)2.8 $\times$ 10^-³ D)6.1 $\times$ 10^-² E)none of these

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Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is Kc = [Ag+(aq)][Cl-(aq)]/[AgCl(s)]. The initial concentration of AgNO3 is 3.9×10^-3 M, and assuming that all of it dissociates, the initial concentration of Ag+ and Cl- is also 3.9×10^-3 M. Letting x be the equilibrium concentration of Cl-, the equilibrium concentrations of Ag+ and AgCl(s) will also be x. Substituting the values into the equilibrium constant expression and solving for x gives x = 2.8×10^-3 M, which is choice C.

Determine the Equilibrium Concentration of the Chloride Ion ×\times× 10-4 B)8 ×\times×

Determine the Equilibrium Concentration of the Chloride Ion $\times$ 10^-⁴
B)8 $\times$