The K_sp for BaF₂ is 2.4 $\times$10^-⁵.When 10 mL of 0.01 M NaF is mixed with 10 mL of 0.01 M BaNO₃,will a precipitate form? A)No,because Q is 1 $\times$ 10^-¹² and since it is less than K_sp no precipitate will form. B)Yes,because Q is 1 $\times$ 10^-¹² and since it is less than K_sp a precipitate will form. C)No,because Q is 1.25 $\times$10^-⁷ and since it is less than K_sp no precipitate will form. D)Yes,because Q is 1.25 $\times$ 10^-⁷ and since it is less than K_sp a precipitate will form. E)None of the above.

Question

Quizplus · Accepted Answer

The reaction quotient (Q) is calculated based on the concentrations of the ions in solution. After mixing, the concentration of each ion is halved due to dilution, making the concentration of F- and Ba2+ each 0.005 M. The Q for the reaction Ba2+ + 2F- -> BaF2 is calculated as [Ba2+][F-]^2 = (0.005)(0.005)^2 = 1.25 x 10^-7. Since this value is less than the Ksp of BaF2 (2.4 x 10^-5), no precipitate will form, indicating that the solution is unsaturated with respect to BaF2.

The Ksp for BaF2 Is 2 ×\times× 10-5 ×\times× 10-12 and Since It Is Less Than Ksp No Precipitate

The K_sp for BaF₂ Is 2 $\times$ 10^-⁵ $\times$ 10^-¹² and Since It Is Less Than K_sp No Precipitate