The diagram below represents a voltaic cell. What is the balanced electrochemical reaction represented by this cell? Al(s)|Al³⁺(1.0 M)||Cu²⁺(1.0 M)|Cu(s)

Question

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The oxidation half-reaction occurs at the anode, which is Al(s)|Al³F1F1F1S1^F1F1F10(1.0 M). The Al atom loses three electrons to form Al3+ ions: Al(s) → Al3+(aq) + 3e- The reduction half-reaction occurs at the cathode, which is Cu²F1F1F1S1^F1F1F10(1.0 M)|Cu(s). The Cu2+ ions in solution gain two electrons to form Cu atoms: Cu2+(aq) + 2e- → Cu(s) Combining these half-reactions gives the balanced electrochemical reaction: 2Al(s) + 3Cu2+(aq) → 3Cu(s) + 2Al3+(aq)

The Diagram Below Represents a Voltaic Cell