The standard molar entropy of silver chloride (AgCl) is 96.2 J/(mol . K). What is the entropy of 1.78 g of AgCl?

Question

Quizplus · Accepted Answer

The entropy of a given amount of substance can be calculated by multiplying the standard molar entropy by the number of moles of the substance. The molar mass of AgCl is approximately 143.32 g/mol, so 1.78 g corresponds to 1.78 g / 143.32 g/mol = 0.0124 mol. The entropy is then 0.0124 mol * 96.2 J/(mol·K) = 1.19 J/K, which is a positive value, indicating an increase in entropy.

The Standard Molar Entropy of Silver Chloride (AgCl) Is 96