A reaction is run under conditions where the equilibrium constant is known to be 2.5. *10². At equilibrium, the forward rate is determined to be 5.0 *10^-⁴ mol L^-¹ s^-¹. What is the rate of the reverse reaction under these conditions?

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The Answer of A reaction is run under conditions where the equilibrium constant is known to be 2.5. *10². At equilibrium, the forward rate is determined to be 5.0 *10^-⁴ mol L^-¹ s^-¹. What is the rate of the reverse reaction under these conditions?

A Reaction Is Run Under Conditions Where the Equilibrium Constant