Two moles of NH₃ are initially present for the reaction: 2 NH₃(g) ⇌ N₂(g) + 3 H₂(g)
At equilibrium there is 1.00 mol NH₃. How many moles of H₂ are present at equilibrium?

Question

Two moles of NH₃ are initially present for the reaction: 2 NH₃(g) ⇌ N₂(g) + 3 H₂(g) At equilibrium there is 1.00 mol NH₃. How many moles of H₂ are present at equilibrium?

Quizplus · Accepted Answer

According to the balanced chemical equation, for every 2 moles of NH₃ that react, 3 moles of H₂ are produced. At equilibrium, there is 1 mole of NH₃ present, which means that 3/2 moles of H₂ must be present to satisfy the stoichiometry of the reaction. Therefore, the answer is 1.50 moles or choice C.

Two Moles of NH3 Are Initially Present for the Reaction

Two Moles of NH₃ Are Initially Present for the Reaction