Given the following information, calculate ΔH°(in kcal mol-1) for: Cl(g) + e- → Cl-(g) Process ΔH° (kcal mol-1)
Li(s) → Li(g) +37
Li(g) → Li+(g) + e- +124
Cl2(g) → 2Cl(g) +58 (per mole Cl2)
LiCl(s) → Li+(g) + Cl-(g) +216
2Li(s) + Cl2(g) → 2LiCl(s) -109 (per mole LiCl)
A) + 83 kcal mol-1
B) -83 kcal mol-1
C) 161 kcal mol-1
D) -112 kcal mol-1
E) 190 kcal mol-1
Correct Answer:
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