Given the following information, calculate ΔH°(in kcal mol-1) for: CaI₂(s) → Ca⁺²(g) +2 I-(g)

Question

Quizplus · Accepted Answer

To calculate ΔH°, we need to use the enthalpies of formation of the products and reactants. ΔH° = ΣnΔH°(products) - ΣnΔH°(reactants) We can use the following values: ΔH°f(CaI₂) = 0 kcal mol-1 (given) ΔH°f(Ca⁺²) = -118 kcal mol-1 (from a table of thermodynamic values) ΔH°f(I-) = 0 kcal mol-1 (I2(s) is the reference state for halogens, and has a ΔH°f of 0 kcal mol-1) ΔH°f(⁺²) = 104 kcal mol-1 (from a table of thermodynamic values) ΔH° = (1*(-118) + 2*104 + 0) - (1*0 + 12*0 + 1*0) ΔH° = 128 kcal mol-1 The answer closest to this value is E: 1288 kcal mol^-1.

Given the Following Information, Calculate ΔH°(in Kcal Mol-1) For: CaI2(s)

Given the Following Information, Calculate ΔH°(in Kcal Mol-1) For: CaI₂(s)