Given the following information, calculate ΔH°(in kcal mol-1) for: LiCl(s) → Cl-(g) + Li+(g) Process ΔH° (kcal mol-1)
Li(s) → Li(g) +37
Li(g) → Li+(g) + e- +124
Cl2(g) → 2Cl(g) +29 (per mole Cl)
Cl(g) + e- → Cl-(g) -83
2Li(s) + Cl2(g) → 2LiCl(s) -109 (per mole LiCl)
A) +73 kcal mol-1
B) +148 kcal mol-1
C) +216 kcal mol-1
D) -96 kcal mol-1
E) -49 kcal mol-1
Correct Answer:
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