Combine the Reactions: P₄(s) + 6 Cl₂(g) → 4 PCl₃(g)

Combine the reactions: P₄(s) + 6 Cl₂(g) → 4 PCl₃(g) ΔH°298 = -1225.0 kJ
PCl₃(g) + 3 H₂O(l) → H₃PO₃(aq) + 3 HCl(aq) = - 853.5 kJ
2 H₂(g) + O₂(g) → 2 H₂O(l) = - 571.5 kJ
H₂(g) + Cl₂(g) → 2 HCl(g) = - 184.9 kJ
To obtain the reaction: P₄(s) + 6 H₂(g) + 6 O₂(g) → 4 H₃PO₃(aq) .
What is the value of ΔH°298 for this reaction?

A) -2465.1 kJ
B) -6958.6 kJ
C) -2834.9 kJ
D) -9177.4 kJ
E) 8605.9 kJ