How many grams of N₂ are required to react with 2.30 moles of Mg in the following process? 3 Mg + N₂ → Mg₃N₂? (Mg = 24.3 g/mol, N = 14.0 g/mol)

Question

Quizplus · Accepted Answer

To find the grams of N₂ needed, first determine the moles of N₂ required using the stoichiometry of the reaction. The balanced equation shows that 3 moles of Mg react with 1 mole of N₂. Therefore, 2.30 moles of Mg will react with 2.30/3 = 0.767 moles of N₂. The molar mass of N₂ is 28.0 g/mol (2 x 14.0 g/mol), so 0.767 moles of N₂ is 0.767 x 28.0 = 21.5 grams.

How Many Grams of N2 Are Required to React with 2.30

How Many Grams of N₂ Are Required to React with 2.30