How many moles of H₃PO₄ are produced when 20.0 g of HCl are produced by the reaction PCl₅ + 4 H₂O → H₃PO₄ + 5 HCl?

Question

Quizplus · Accepted Answer

1 mole of PCl5 reacts with 4 moles of H2O to produce 5 moles of HCl.
The molar mass of HCl = 36.5 g/mol
Number of moles of HCl produced = (20.0 g)/(36.5 g/mol) = 0.548 moles
According to the balanced chemical equation, 1 mole of PCl5 reacts with 4 moles of H2O to produce 1 mole of HSbF6 and 5 moles of HCl.
So, 0.548 moles of HCl will react with (0.548/5) moles of HSbF6.
The molar mass of HSbF6 = 261.8 g/mol
Therefore, the mass of HSbF6 formed = (0.548/5) mol x 261.8 g/mol = 28.5 g/mol
But the question asks for the number of moles produced, so we need to divide by the molar mass of HSbF6:
Number of moles HSbF6 produced = 28.5 g/(261.8 g/mol) = 0.109 mol
Therefore, the answer is option C.

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