Consider the reaction: 2 C₂H₆(g)+ 7 O₂(g)$\rightarrow$ 4 CO₂(g)+ 6 H₂O(g). Decreasing the concentration of C₂H₆(g)will decrease the reaction rate.

Question

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According to Le Chatelier's principle, decreasing the concentration of a reactant will shift the equilibrium towards the side with more reactants, in order to establish a new equilibrium. In this case, decreasing the concentration of C₂H₆(g) will cause the equilibrium to shift towards the left side of the equation, meaning less product will be formed. As a result, the reaction rate will decrease.

Consider the Reaction: 2 C2H6(g)+ 7 O2(g) →\rightarrow→ 4 CO2(g)+ 6 H2O(g)

Consider the Reaction: 2 C₂H₆(g)+ 7 O₂(g) $\rightarrow$ 4 CO₂(g)+ 6 H₂O(g)