One mole of a liquid is vaporized at its boiling point, 65°C and 1.00 atm. $\Delta$H vap for the liquid is 43.8 kJ/mol at 65° C.
-Calculate $\Delta$E.

Name: One mole of a liquid is vaporized at its boiling point, 65°C and 1.00 atm. $\Delta$H vap for the liquid is 43.8 kJ/mol at 65° C. -Calculate $\Delta$E.
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The Answer of One mole of a liquid is vaporized at its boiling point, 65°C and 1.00 atm. $\Delta$H vap for the liquid is 43.8 kJ/mol at 65° C.
-Calculate $\Delta$E.

One Mole of a Liquid Is Vaporized at Its Boiling Δ\DeltaΔ

One Mole of a Liquid Is Vaporized at Its Boiling $\Delta$