Use the Following Table: Reaction $\Delta$ H° (KJ)
I $\rightarrow$ 4PCl₃(g)
-1225 $\rightarrow$

Use the following table: Reaction
$\Delta$ H° (kJ)
I. P₄(s) + 6Cl₂(g) $\rightarrow$ 4PCl₃(g)
-1225.6
II. P₄(s) + 5O₂(g) $\rightarrow$ P₄O₁₀(g)
-2967.3
III. PCl₃(g) + Cl₂(g) $\rightarrow$ PCl₅(g)
-84.2
IV. PCl₃(g) + (1/2) O₂(g) $\rightarrow$ Cl₃PO(g)
-285.7
Calculate $\Delta$ H° for the reaction
P₄O₁₀(g) + 6PCl₅(g) $\rightarrow$ 10Cl₃PO(g)

A) -610.1 kJ
B) -2682.2 kJ
C) -7555.0 kJ
D) -110.5 kJ
E) None of these is within 5% of the correct answer.