Consider the following standard heats of formation:
P₄O₁₀(s)= -3110 kJ/mol
H₂O(l)= -286 kJ/mol
H₃PO₄(s)= -1279 kJ/mol
Calculate the change in enthalpy for the following process:
P₄O₁₀(s)+ 6H₂O(l) $\to$ 4H₃PO₄(s)

Question

Consider the following standard heats of formation:
P₄O₁₀(s)= -3110 kJ/mol
H₂O(l)= -286 kJ/mol
H₃PO₄(s)= -1279 kJ/mol
Calculate the change in enthalpy for the following process:
P₄O₁₀(s)+ 6H₂O(l)

\to

4H₃PO₄(s)

Quizplus · Accepted Answer

The Answer of Consider the following standard heats of formation: P₄O₁₀(s)= -3110 kJ/mol H₂O(l)= -286 kJ/mol H₃PO₄(s)= -1279 kJ/mol Calculate the change in enthalpy for the following process: P₄O₁₀(s)+ 6H₂O(l)$\to$4H₃PO₄(s)

Consider the Following Standard Heats of Formation: P4O10(s)= -3110 KJ/mol →\to→

Consider the Following Standard Heats of Formation:
P₄O₁₀(s)= -3110 KJ/mol $\to$