What quantity of charge is required to reduce 31.2 g of CrCl3 to chromium metal? (1 faraday = 96,485 coulombs)
A) 3.80 *104 C
B) 7.60* 104 C
C) 5.70 *104 C
D) 1.74 * 105 C
E) 1.90 *104 C
Correct Answer:
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