Fe²⁺ + 2e^- $\rightarrow$Fe(s) E° = -0.440 V 2H⁺ + 2e^- $\rightarrow$H₂(g) E° = 0.000 V In a galvanic cell, the iron compartment contains an iron electrode, and [Fe²⁺] = 1.00 *10^-³ M. The hydrogen compartment contains a platinum electrode (P_H2 = 1.00 atm) and a weak acid HA at an initial concentration of 1.00 M. If the observed cell potential is 0.333 V at 25°C, calculate K_a for the weak acid HA at 25°C.

Question

Quizplus · Accepted Answer

The Answer of Fe²⁺ + 2e^- $\rightarrow$Fe(s) E° = -0.440 V 2H⁺ + 2e^- $\rightarrow$H₂(g) E° = 0.000 V In a galvanic cell, the iron compartment contains an iron electrode, and [Fe²⁺] = 1.00 *10^-³ M. The hydrogen compartment contains a platinum electrode (P_H2 = 1.00 atm) and a weak acid HA at an initial concentration of 1.00 M. If the observed cell potential is 0.333 V at 25°C, calculate K_a for the weak acid HA at 25°C.

Fe2+ + 2e- →\rightarrow→ Fe(s) E° = -0 →\rightarrow→ H2(g) E° = 0

Fe²⁺ + 2e^- $\rightarrow$ Fe(s) E° = -0 $\rightarrow$ H₂(g) E° = 0