In the following equation $\Delta$G = $\Delta$G° + RT nK

Question

Quizplus · Accepted Answer

According to the van 't Hoff equation, ln(K) = -ΔH/R(1/T), where K is the equilibrium constant, ΔH is the enthalpy change, R is the gas constant, and T is the temperature. In the given equation, there is no enthalpy change mentioned, so we can assume it to be zero. Therefore, ln(K) = 0, which implies that K = 1. Also, since the standard free energy change (ΔG°) is mentioned in the equation, we can infer that ΔG° = F1F1F1S1F1F1F10G°. Therefore, (F1F1F1S1F1F1F10G = F1F1F1S1F1F1F10G° + RT) can be rewritten as (F1F1F1S1F1F1F10G - F1F1F1S1F1F1F10G° = -RT), which is the equation for ΔG. At equilibrium, ΔG = 0, which implies that (F1F1F1S1F1F1F10G - F1F1F1S1F1F1F10G° = 0), or F1F1F1S1F1F1F10G = F1F1F1S1F1F1F10G°. Therefore, the correct choice is D, (F1F1F1S1F1F1F10G = 0).

In the Following Equation Δ\DeltaΔ G = Δ\DeltaΔ G° + RT NK A) K = 1 B)

In the Following Equation $\Delta$ G = $\Delta$ G° + RT NK
A) K = 1
B)