The specific heat of lead is 0.030 cal/g. °C.300 g of lead shot at 100°C is mixed with 100 g of water at 70°C in an insulated container.The final temperature of the mixture is:

Question

Quizplus · Accepted Answer

The heat lost by lead equals the heat gained by water. Using the formula $m \cdot c \cdot \Delta T$, where $m$ is mass, $c$ is specific heat, and $\Delta T$ is the change in temperature, we set up the equation: $300 \cdot 0.030 \cdot (100 - T) = 100 \cdot 1 \cdot (T - 70)$. Solving for $T$ gives approximately 72.5°C.

The Specific Heat of Lead Is 0