How many calories are required to change one gram of 0°C ice to 100°C steam? The latent heat of fusion is 80 cal/g and the latent heat of vaporization is 540 cal/g.The specific heat of water is 1.00 cal/g ° K.

Question

Quizplus · Accepted Answer

To calculate the total calories required to change one gram of 0°C ice to 100°C steam, we need to consider three stages: melting the ice, heating the water from 0°C to 100°C, and vaporizing the water into steam. 1. Melting the ice requires 80 cal/g (latent heat of fusion).2. Heating the water from 0°C to 100°C requires 1.00 cal/g°C * 100°C = 100 cal.3. Vaporizing the water into steam requires 540 cal/g (latent heat of vaporization).Adding these together: 80 cal + 100 cal + 540 cal = 720 cal.

How Many Calories Are Required to Change One Gram of 0°C