The heat capacity of object B is twice that of object A.Initially A is at 300 K and B is at 450 K.They are placed in thermal contact and the combination is isolated.The final temperature of both objects is:

Question

Quizplus · Accepted Answer

The final temperature can be found using the principle of conservation of energy. Since the heat capacity of B is twice that of A, the final temperature will be closer to B's initial temperature. The final temperature is calculated as (1*300 + 2*450)/(1+2) = 400 K.

The Heat Capacity of Object B Is Twice That of Object