Given that 50.0 mL of 0.125 M Hg(NO₃) 2 reacts completely with 0.145 M NaI,what volume of sodium iodide is required? Hg(NO₃) 2(aq) + NaI(aq) → HgI₂(s) + NaNO₃(aq)
A) 21.6 mL
B) 29.0 mL
C) 43.1 mL
D) 58.0 mL
E) 86.2 mL
Correct Answer:
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