Given the two-step process for converting aqueous hydrogen sulfide to SF6: 8 H₂S(aq) + 8 Cl₂(g) → 16 HCl(aq) + S8(s)
S8(s) + 24 F2(g) → 8 SF6(g)
What mass of sulfur hexafluoride is produced from 10.0 L of 0.0100 M H₂S?
A) 0.100 g
B) 0.800 g
C) 1.83 g
D) 14.6 g
E) 117 g
Correct Answer:
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