If 0.600 mol of A reacts with 1.00 mol of B according to the following equation,how many moles of C are produced? A(g)+ 2 B(g)→ 3 C(g)

Question

Quizplus · Accepted Answer

1.50 molGiven the stoichiometry of the reaction, A reacts with B in a 1:2 ratio to produce C in a 3:1 ratio with A. Since 0.600 mol of A reacts with 1.00 mol of B, A is the limiting reactant. Therefore, 0.600 mol of A would produce 0.600 * 3 = 1.80 mol of C if B were in excess. However, since B is present in a 1:2 ratio, and we have 1.00 mol of B, which is exactly enough to react with 0.500 mol of A to produce 1.50 mol of C (0.500 mol of A * 3 = 1.50 mol of C), the correct answer is 1.50 mol of C produced.

If 0600 Mol of a Reacts with 1