Given that 0.500 g of NaHCO₃ reacts completely with 0.100 M H₂SO₄,what is the volume of sulfuric acid consumed? NaHCO₃(s)+ H₂SO₄(aq)→ Na₂SO₄(aq)+ H₂O(l)+ CO₂(g)

Question

Quizplus · Accepted Answer

1. Write the balanced chemical equation:

NaHCO₃(s) + H₂SO₄(aq) → Na₂SO₄(aq) + H₂O(l) + CO₂(g)

2. Determine the limiting reagent:

0.500 g NaHCO₃ × (1 mol NaHCO₃ / 84.01 g) = 0.00595 mol NaHCO₃

Since the stoichiometry of the balanced equation is 1:1, 0.00595 mol H₂SO₄ is needed to react completely with 0.00595 mol NaHCO₃.

0.100 M H₂SO₄ = 0.100 mol/L, so:

0.00595 mol H₂SO₄ × (1 L/0.100 mol) = 0.0595 L = 59.5 mL

Therefore, the volume of sulfuric acid consumed is 59.5 mL, or choice B.

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