Given that 0.500 g of NaHCO₃ reacts completely with 0.100 M H₂SO₄,what is the STP volume of carbon dioxide gas produced? NaHCO₃(s)+ H₂SO₄(aq)→ Na₂SO₄(aq)+ H₂O(l)+ CO₂(g)

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First, calculate the moles of NaHCO₃ used: $ \frac{0.500 \, \text{g}}{84.01 \, \text{g/mol}} = 0.00595 \, \text{mol} $. Since the reaction is 1:1, this produces 0.00595 mol of CO₂. At STP, 1 mol of gas occupies 22.4 L, so $ 0.00595 \, \text{mol} \times 22.4 \, \text{L/mol} = 0.133 \, \text{L} $ or 133 mL.

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