What is the volume of 3.00 M sulfuric acid that contains 9.809 g of H₂SO₄ solute (98.09 g/mol)?

Question

Quizplus · Accepted Answer

To find the volume of the solution, we need to use the formula:

n = m/M

where n is moles of solute, m is the mass of solute, and M is the molar mass of solute.

First, let's find the number of moles of H₂SO₄:

n = 9.809 g / 98.09 g/mol = 0.1 mol

Now, we can use the formula:

M = n/V

where M is the molarity of the solution and V is the volume of the solution in liters.

Rearranging this formula to solve for V, we get:

V = n/M

Substituting the values we know:

V = 0.1 mol / 3.00 mol/L = 0.0333 L

Finally, we need to convert this volume to milliliters:

V = 0.0333 L x 1000 mL/L = 33.3 mL

Therefore, the answer is C.

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