What is the molarity of aqueous potassium hydroxide if 42.5 mL of KOH reacts with 25.0 mL of 0.100 M H₃PO₄? H₃PO₄(aq)+ 3 KOH(aq)→ K₃PO₄(aq)+ 3 H₂O(l)

Question

Quizplus · Accepted Answer

The balanced equation shows that 3 moles of KOH react with 1 mole of H₃PO₄. Using the volume and molarity of H₃PO₄, calculate moles of H₃PO₄: 0.025 L * 0.100 M = 0.0025 moles. Therefore, moles of KOH = 3 * 0.0025 = 0.0075 moles. Molarity of KOH = moles/volume = 0.0075 moles / 0.0425 L = 0.176 M.

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