What is the molarity of aqueous lithium bromide if 25.0 mL of LiBr reacts with 10.0 mL of 0.250 M Pb(NO₃)2? Pb(NO₃)2(aq)+ 2 LiBr(aq)→ PbBr₂(s)+ 2 LiNO₃(aq)

Question

Quizplus · Accepted Answer

First, we need to use stoichiometry to determine the amount of moles of Pb(NO₃)2 used in the reaction:

10.0 mL x 0.250 mol/L = 0.00250 mol Pb(NO₃)2

Since the stoichiometric ratio of Pb(NO₃)2 to LiBr is 1:2, we know that twice the number of moles of LiBr must have reacted:

2 x 0.00250 mol = 0.00500 mol LiBr

Finally, we can use the definition of molarity to calculate the concentration of LiBr:

M = mol/L
M = 0.00500 mol / (25.0 mL / 1000 mL/L)
M = 0.200 M

Therefore, the answer is C (0.200 M).

What Is the Molarity of Aqueous Lithium Bromide If 25