If a genome is sequenced in such a way that any given nucleotide is present in n sequenced fragments, then if each nucleotide is equally likely to be sequenced, the expected proportion of nucleotides that are not present in any of the fragments is given by e^-ⁿ, where e is the base of natural logarithms. (The value of e is approximately 2.7182.) What is the probability that a nucleotide is not sequenced if n = 1? If n = 2? If n = 3?

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The Answer of If a genome is sequenced in such a way that any given nucleotide is present in n sequenced fragments, then if each nucleotide is equally likely to be sequenced, the expected proportion of nucleotides that are not present in any of the fragments is given by e^-ⁿ, where e is the base of natural logarithms. (The value of e is approximately 2.7182.) What is the probability that a nucleotide is not sequenced if n = 1? If n = 2? If n = 3?

If a Genome Is Sequenced in Such a Way That