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Portions of a Management Scientist Output Are Shown Below 3X1+5X2+4X3<1503 \mathrm { X } 1 + 5 \mathrm { X } 2 + 4 \mathrm { X } 3 < 150

Question 58

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Portions of a Management Scientist output are shown below.Use what you know about the solution of linear programs to fill in the ten blanks.
LINEAR PROGRAMMING PROBLEM
MAX 12X1+9X2+7X3
S.T.
OPTIMAL SOLUTION
Objective Function Value = 336.000
1) 3X1+5X2+4X3<1503 \mathrm { X } 1 + 5 \mathrm { X } 2 + 4 \mathrm { X } 3 < 150
2) 2X1+1X2+1X3<642 \mathrm { X } 1 + 1 \mathrm { X } 2 + 1 \mathrm { X } 3 < 64
3) 1X1+2X2+1X3<801 \mathrm { X } 1 + 2 \mathrm { X } 2 + 1 \mathrm { X } 3 < 80
4) 2X1+4X2+3X3>1162 X 1 + 4 X 2 + 3 X 3 > 116  Portions of a Management Scientist output are shown below.Use what you know about the solution of linear programs to fill in the ten blanks. LINEAR PROGRAMMING PROBLEM MAX 12X1+9X2+7X3 S.T. OPTIMAL SOLUTION Objective Function Value = 336.000  1)  3 \mathrm { X } 1 + 5 \mathrm { X } 2 + 4 \mathrm { X } 3 < 150  2)  2 \mathrm { X } 1 + 1 \mathrm { X } 2 + 1 \mathrm { X } 3 < 64  3)  1 \mathrm { X } 1 + 2 \mathrm { X } 2 + 1 \mathrm { X } 3 < 80  4)  2 X 1 + 4 X 2 + 3 X 3 > 116    OBJECTIVE COEFFICIENT RANGES    RIGHT HAND SIDE RANGES   \begin{array} { l l c l }  \text { Variable } & \text { Lower Limit } & \text { Current Value } & \text { Upper Limit } \\ \mathrm { X } 1 & 5.400 & 12.000 & \text { No Upper Limit } \\ \mathrm { X } 2 & 2.000 & 9.000 & 20.000 \\ \mathrm { X } 3 & \text { No Lower Limit } & 7.000 & 10.500 \end{array}    OBJECTIVE COEFFICIENT RANGES
 Portions of a Management Scientist output are shown below.Use what you know about the solution of linear programs to fill in the ten blanks. LINEAR PROGRAMMING PROBLEM MAX 12X1+9X2+7X3 S.T. OPTIMAL SOLUTION Objective Function Value = 336.000  1)  3 \mathrm { X } 1 + 5 \mathrm { X } 2 + 4 \mathrm { X } 3 < 150  2)  2 \mathrm { X } 1 + 1 \mathrm { X } 2 + 1 \mathrm { X } 3 < 64  3)  1 \mathrm { X } 1 + 2 \mathrm { X } 2 + 1 \mathrm { X } 3 < 80  4)  2 X 1 + 4 X 2 + 3 X 3 > 116    OBJECTIVE COEFFICIENT RANGES    RIGHT HAND SIDE RANGES   \begin{array} { l l c l }  \text { Variable } & \text { Lower Limit } & \text { Current Value } & \text { Upper Limit } \\ \mathrm { X } 1 & 5.400 & 12.000 & \text { No Upper Limit } \\ \mathrm { X } 2 & 2.000 & 9.000 & 20.000 \\ \mathrm { X } 3 & \text { No Lower Limit } & 7.000 & 10.500 \end{array}    RIGHT HAND SIDE RANGES
 Variable  Lower Limit  Current Value  Upper Limit X15.40012.000 No Upper Limit X22.0009.00020.000X3 No Lower Limit 7.00010.500\begin{array} { l l c l } \text { Variable } & \text { Lower Limit } & \text { Current Value } & \text { Upper Limit } \\\mathrm { X } 1 & 5.400 & 12.000 & \text { No Upper Limit } \\\mathrm { X } 2 & 2.000 & 9.000 & 20.000 \\\mathrm { X } 3 & \text { No Lower Limit } & 7.000 & 10.500\end{array}  Portions of a Management Scientist output are shown below.Use what you know about the solution of linear programs to fill in the ten blanks. LINEAR PROGRAMMING PROBLEM MAX 12X1+9X2+7X3 S.T. OPTIMAL SOLUTION Objective Function Value = 336.000  1)  3 \mathrm { X } 1 + 5 \mathrm { X } 2 + 4 \mathrm { X } 3 < 150  2)  2 \mathrm { X } 1 + 1 \mathrm { X } 2 + 1 \mathrm { X } 3 < 64  3)  1 \mathrm { X } 1 + 2 \mathrm { X } 2 + 1 \mathrm { X } 3 < 80  4)  2 X 1 + 4 X 2 + 3 X 3 > 116    OBJECTIVE COEFFICIENT RANGES    RIGHT HAND SIDE RANGES   \begin{array} { l l c l }  \text { Variable } & \text { Lower Limit } & \text { Current Value } & \text { Upper Limit } \\ \mathrm { X } 1 & 5.400 & 12.000 & \text { No Upper Limit } \\ \mathrm { X } 2 & 2.000 & 9.000 & 20.000 \\ \mathrm { X } 3 & \text { No Lower Limit } & 7.000 & 10.500 \end{array}

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x3 = 0 because the reduced cost is positi...

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