Calculate the percent ionization of a 0.050 M aqueous solution of HF having a pH of 3.15.

Name: Calculate the percent ionization of a 0.050 M aqueous solution of HF having a pH of 3.15.
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Question

Quizplus · Accepted Answer

The percent ionization is calculated using the formula: % ionization = ([H⁺]/[HF_initial]) * 100. From the pH of 3.15, [H⁺] = 10^(-3.15) = 7.08 x 10^(-4) M. Thus, % ionization = (7.08 x 10^(-4) / 0.050) * 100 = 1.4%.

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