Calculate the percent ionization of a 0.200 M aqueous solution of HNO₂ having a pH of 2.80.

Question

Quizplus · Accepted Answer

The percent ionization can be calculated using the following equation:$$	ext{% ionization} = \frac{[	ext{H}^+]	imes100}{	ext{initial concentration}}$$Substituting the given values into the equation:$$	ext{% ionization} = \frac{10^{-2.80}	imes100}{0.200 	ext{ M}} = 0.79%$$Therefore, the percent ionization of the solution is 0.79%.

Calculate the Percent Ionization of a 0