An aqueous mixture of phenol and ammonia has initial concentrations of 0.200 M C₆H₅OH(aq)and 0.120 M NH₃(aq).At equilibrium,the C₆H₅O^-(aq)concentration is 0.050 M.Calculate the equilibrium constant,K,for the reaction below. C₆H₅OH(aq)+ NH₃(aq) C₆H₅O^- + NH₄⁺(aq)

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is:
$$K=\frac{[	ext{CSOH}][	ext{NHS}	ext{_3}]}{[	ext{CSP}-][	ext{NHS}_2^+]}$$
Using the given equilibrium concentrations:
$$K=\frac{(0.050)(0.120)}{(0.200-0.050)(0.120-0.050)}=0.24$$
Therefore, the answer is choice B.

An Aqueous Mixture of Phenol and Ammonia Has Initial Concentrations