Calculate the heat transfer, in J, when 5.00 g of chromium (specific heat capacity = 0.449 J g^-1 °C^-1) at 0.00 °C is placed in 50.0 mL of water. The final temperature of the water is 23.8 °C. The chromium is defined as the system in this scenario.

Question

Quizplus · Accepted Answer

First, we need to calculate the heat transferred from the chromium to the water using the formula:
q = m × c × ΔT
Where q is heat transferred, m is the mass of chromium, c is the specific heat capacity of chromium, and ΔT is the change in temperature.

q = (5.00 g) × (0.449 J/g°C) × (-23.8°C - 0.00°C) = -53.54 J (note that we use -23.8°C because heat is transferred from the chromium to the water, so the chromium loses heat and its temperature decreases)

The negative sign indicates that heat is transferred from the chromium to the water, which makes sense because the final temperature of the water is higher than the initial temperature of the chromium.

Therefore, the correct answer is B) 53 J.

Calculate the Heat Transfer, in J, When 5