Question 1

A free electron is in an electric field. With respect to the field, it experiences a force acting:

Accepted Answer

A free electron experiences a force in the direction opposite to the electric field because it has a negative charge.

Question 2

The unit of electrical potential, the volt, is dimensionally equivalent to:

Accepted Answer

The volt (V) is defined as the potential difference that will move one coulomb (C) of charge with one joule (J) of energy. Therefore, 1 volt is equivalent to 1 joule per coulomb (J/C).

Question 3

Two protons, each of charge 1.60 *10 ^- ¹⁹ C, are 3.00 *10 ^- ⁵ m apart. What is the change in potential energy if they are brought 1.00 *10 ^- ⁵ m closer together? (k_e = 8.99 *10⁹ N·m²/C²)

Accepted Answer

The change in potential energy is given by:$$\Delta U = k_e \frac{q_1 q_2}{r_f} - k_e \frac{q_1 q_2}{r_i}$$where:* $k_e$ is the Coulomb constant* $q_1$ and $q_2$ are the charges of the protons* $r_f$ is the final distance between the protons* $r_i$ is the initial distance between the protonsSubstituting the given values into the equation, we get:$$\Delta U = (8.99 	imes 10^9 	ext{ N$\cdot$m}^2/	ext{C}^2) \frac{(1.60 	imes 10^{-19} 	ext{ C})^2}{1.00 	imes 10^{-5} 	ext{ m}} - (8.99 	imes 10^9 	ext{ N$\cdot$m}^2/	ext{C}^2) \frac{(1.60 	imes 10^{-19} 	ext{ C})^2}{2.00 	imes 10^{-5} 	ext{ m}}$$$$\Delta U = 3.84 	imes 10^{-24} 	ext{ J}$$Therefore, the change in potential energy is 3.84 x 10^-24 J.

Question 4

Which of the following characteristics are held in common by both gravitational and electrostatic forces when dealing with either point masses or charges?

Accepted Answer

Both gravitational and electrostatic forces have potential energy that depends on the distance of separation, are conservative forces, and follow the inverse square law.

Question 5

A proton (+1.6 *10 ^- ¹⁹C) moves 10 cm along the direction of an electric field of strength 4.0 N/C. The electrical potential difference between the proton's initial and ending points is:

Accepted Answer

The potential difference (V) is calculated using V = E * d, where E is the electric field strength (4.0 N/C) and d is the distance (0.10 m). Thus, V = 4.0 N/C * 0.10 m = 0.40 V.

Question 6

A uniform electric field, with a magnitude of 600 N/C, is directed parallel to the positive x axis. If the potential at x = 4.0 m is 1000 V, what is the potential at x = 2.0 m?

Accepted Answer

The answer of A uniform electric field, with a magnitude...

Question 7

Two point charges of values +3.4 $\mu$C and +6.6 $\mu$C, respectively, are separated by 0.20 m. What is the potential energy of this 2-charge system? (k_e = 8.99* 10⁹ N.m²/C²)

Accepted Answer

The answer of Two point charges of values +3.4 $\mu$C...

Question 8

An electron and a proton are each released from rest in the same uniform electric field. The electron moves a distance d_electron and the proton moves a distance d_proton as each particle's kinetic energy increases by 1.6 eV. How do d_electron and d_proton compare?

Accepted Answer

The answer of An electron and a proton are each...

Question 9

If an electron is accelerated from rest through a potential difference of 300 V, find its approximate speed at the end of this process. (e = 1.6 * 10 ^- ¹⁹ C; m_e = 9.1 *10 ^- ³¹ kg)

Accepted Answer

The answer of If an electron is accelerated from rest...

Question 10

If the distance between two isolated parallel plates that are oppositely charged is doubled, the electric field between the plates is essentially unchanged. However, the:

Accepted Answer

The electric field between parallel plates is constant, but the potential difference is proportional to the distance between the plates. Doubling the distance doubles the potential difference.

Question 11

An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plates is 5.0 mm and the potential difference across the plates is 20 V, with what velocity does the electron hit the positive plate? (m_e = 9.1 * 10 ^- ³¹ kg, e = 1.6 *10 ^- ¹⁹ C)

Accepted Answer

The kinetic energy gained by the electron equals the work done by the electric field, which is the charge times the potential difference: KE = eV. Solving for velocity using KE = 0.5 * m * v^2 gives v = sqrt(2 * e * V / m). Substituting the given values results in approximately 2.7 x 10^6 m/s.

Question 12

The quantity of electrical potential, the volt, is dimensionally equivalent to:

Accepted Answer

The answer of The quantity of electrical potential, the volt,...

Question 13

A uniform electric field, with a magnitude of 600 N/C, is directed parallel to the positive x axis. If the potential at x = 4.0 m is 1000 V, what is the change in potential energy of a proton as it moves from x = 4.0 m to x = 1.0 m? (q_p = 1.6 *10 ^- ¹⁹ C)

Accepted Answer

The change in potential energy of a proton as it moves from x = 4.0 m to x = 1.0 m is given by:$$\Delta U = q\Delta V = (1.6 	imes 10^{-19} C)(1000 V - 600 V/m * 3.0 m) = 2.9 	imes 10^{-16} J$$

Question 14

Two particles each have the same mass but particle #1 has four times the charge of particle #2. Particle #1 is accelerated from rest through a potential difference of 10 V and attains speed v. Particle #2 is accelerated from rest also through a potential difference of 10 V. What speed does particle #2 attain?

Accepted Answer

The answer of Two particles each have the same mass...

Question 15

Case 1: An electron is released from rest in a uniform electric field. Case 2: A proton is released from rest in a uniform electric field of the same magnitude as in case 1. How does the electric potential energy of the charge-field system behave in these cases?

Accepted Answer

The electric potential energy of a charge-field system is given by the equation U = qV, where q is the charge and V is the electric potential. In case 1, the electron has a negative charge, so its potential energy will decrease as it moves in the electric field. In case 2, the proton has a positive charge, so its potential energy will increase as it moves in the electric field.

Question 16

An electron in a cathode ray tube is accelerated through a potential difference of 10 kV. What kinetic energy does the electron gain in the process? (e = 1.6 * 10 ^- ¹⁹C)

Accepted Answer

The kinetic energy gained by the electron is equal to the charge of the electron multiplied by the potential difference: KE = eV = (1.6 x 10^-19 C)(10,000 V) = 1.6 x 10^-15 J.

Question 17

In which case does an electric field do positive work on a charged particle?

Accepted Answer

When a negative charge moves opposite to the direction of the electric field, the field does positive work on the charge, as it moves in the direction of the force exerted by the field.

Question 18

If the distance between two negative point charges is increased by a factor of two, the resultant potential energy is what factor times the initial potential energy?

Accepted Answer

The answer of If the distance between two negative point...

Question 19

An electron (charge -1.6 *10 ^- ¹⁹C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C. How much work is done on the electron as it moves 20 cm?

Accepted Answer

Work done by an electric field on a charge is given by W = qEd cos(θ), where θ is the angle between the field and the path. Since the electron moves perpendicular to the electric field, θ = 90°, and cos(90°) = 0, so the work done is zero.

Question 20

A proton (+1.6 *10 ^- ¹⁹ C) moves 10 cm on a path in the direction opposite to a uniform electric field of strength 3.0 N/C. How much work is done on the proton by the electrical field?

Accepted Answer

The work done by the electric field is calculated using the formula W = -qEd, where q is the charge, E is the electric field strength, and d is the distance. Since the proton moves opposite to the field, the work done is negative: W = -(1.6 x 10^-19 C)(3.0 N/C)(0.1 m) = -4.8 x 10^-20 J.

Quiz 18: Electric Potential

A free electron is in an electric field. With respect to the field, it experiences a force acting:

The unit of electrical potential, the volt, is dimensionally equivalent to:

Two protons, each of charge 1.60 10 ^- ¹⁹ C, are 3.00 10 ^- ⁵ m apart. What is the change in potential energy if they are brought 1.00 10 ^- ⁵ m closer together? (k_e = 8.99 10⁹ N·m²/C²)

Which of the following characteristics are held in common by both gravitational and electrostatic forces when dealing with either point masses or charges?

A proton (+1.6 *10 ^- ¹⁹C) moves 10 cm along the direction of an electric field of strength 4.0 N/C. The electrical potential difference between the proton's initial and ending points is:

A uniform electric field, with a magnitude of 600 N/C, is directed parallel to the positive x axis. If the potential at x = 4.0 m is 1000 V, what is the potential at x = 2.0 m?

Two point charges of values +3.4 $\mu$ C and +6.6 $\mu$ C, respectively, are separated by 0.20 m. What is the potential energy of this 2-charge system? (k_e = 8.99* 10⁹ N.m²/C²)

An electron and a proton are each released from rest in the same uniform electric field. The electron moves a distance d_electron and the proton moves a distance d_proton as each particle's kinetic energy increases by 1.6 eV. How do d_electron and d_proton compare?

If an electron is accelerated from rest through a potential difference of 300 V, find its approximate speed at the end of this process. (e = 1.6 * 10 ^- ¹⁹ C; m_e = 9.1 *10 ^- ³¹ kg)

If the distance between two isolated parallel plates that are oppositely charged is doubled, the electric field between the plates is essentially unchanged. However, the:

An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plates is 5.0 mm and the potential difference across the plates is 20 V, with what velocity does the electron hit the positive plate? (m_e = 9.1 * 10 ^- ³¹ kg, e = 1.6 *10 ^- ¹⁹ C)

The quantity of electrical potential, the volt, is dimensionally equivalent to:

A uniform electric field, with a magnitude of 600 N/C, is directed parallel to the positive x axis. If the potential at x = 4.0 m is 1000 V, what is the change in potential energy of a proton as it moves from x = 4.0 m to x = 1.0 m? (q_p = 1.6 *10 ^- ¹⁹ C)

Case 1: An electron is released from rest in a uniform electric field. Case 2: A proton is released from rest in a uniform electric field of the same magnitude as in case 1. How does the electric potential energy of the charge-field system behave in these cases?

An electron in a cathode ray tube is accelerated through a potential difference of 10 kV. What kinetic energy does the electron gain in the process? (e = 1.6 * 10 ^- ¹⁹C)

In which case does an electric field do positive work on a charged particle?

If the distance between two negative point charges is increased by a factor of two, the resultant potential energy is what factor times the initial potential energy?

An electron (charge -1.6 *10 ^- ¹⁹C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C. How much work is done on the electron as it moves 20 cm?

A proton (+1.6 *10 ^- ¹⁹ C) moves 10 cm on a path in the direction opposite to a uniform electric field of strength 3.0 N/C. How much work is done on the proton by the electrical field?

Quiz 18: Electric Potential

A free electron is in an electric field. With respect to the field, it experiences a force acting:

The unit of electrical potential, the volt, is dimensionally equivalent to:

Two protons, each of charge 1.60 *10 - 19 C, are 3.00 *10 - 5 m apart. What is the change in potential energy if they are brought 1.00 *10 - 5 m closer together? (ke = 8.99 *109 N·m2/C2)

Which of the following characteristics are held in common by both gravitational and electrostatic forces when dealing with either point masses or charges?

A proton (+1.6 *10 - 19 C) moves 10 cm along the direction of an electric field of strength 4.0 N/C. The electrical potential difference between the proton's initial and ending points is:

A uniform electric field, with a magnitude of 600 N/C, is directed parallel to the positive x axis. If the potential at x = 4.0 m is 1000 V, what is the potential at x = 2.0 m?

Two point charges of values +3.4 μ\muμ C and +6.6 μ\muμ C, respectively, are separated by 0.20 m. What is the potential energy of this 2-charge system? (ke = 8.99* 109 N.m2/C2)

An electron and a proton are each released from rest in the same uniform electric field. The electron moves a distance delectron and the proton moves a distance dproton as each particle's kinetic energy increases by 1.6 eV. How do delectron and dproton compare?

If an electron is accelerated from rest through a potential difference of 300 V, find its approximate speed at the end of this process. (e = 1.6 * 10 - 19 C; me = 9.1 *10 - 31 kg)

If the distance between two isolated parallel plates that are oppositely charged is doubled, the electric field between the plates is essentially unchanged. However, the:

An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plates is 5.0 mm and the potential difference across the plates is 20 V, with what velocity does the electron hit the positive plate? (me = 9.1 * 10 - 31 kg, e = 1.6 *10 - 19 C)

The quantity of electrical potential, the volt, is dimensionally equivalent to:

A uniform electric field, with a magnitude of 600 N/C, is directed parallel to the positive x axis. If the potential at x = 4.0 m is 1000 V, what is the change in potential energy of a proton as it moves from x = 4.0 m to x = 1.0 m? (qp = 1.6 *10 - 19 C)

Case 1: An electron is released from rest in a uniform electric field. Case 2: A proton is released from rest in a uniform electric field of the same magnitude as in case 1. How does the electric potential energy of the charge-field system behave in these cases?

An electron in a cathode ray tube is accelerated through a potential difference of 10 kV. What kinetic energy does the electron gain in the process? (e = 1.6 * 10 - 19 C)

In which case does an electric field do positive work on a charged particle?

If the distance between two negative point charges is increased by a factor of two, the resultant potential energy is what factor times the initial potential energy?

An electron (charge -1.6 *10 - 19 C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C. How much work is done on the electron as it moves 20 cm?

A proton (+1.6 *10 - 19 C) moves 10 cm on a path in the direction opposite to a uniform electric field of strength 3.0 N/C. How much work is done on the proton by the electrical field?

Two protons, each of charge 1.60 10 ^- ¹⁹ C, are 3.00 10 ^- ⁵ m apart. What is the change in potential energy if they are brought 1.00 10 ^- ⁵ m closer together? (k_e = 8.99 10⁹ N·m²/C²)

A proton (+1.6 *10 ^- ¹⁹C) moves 10 cm along the direction of an electric field of strength 4.0 N/C. The electrical potential difference between the proton's initial and ending points is:

Two point charges of values +3.4 $\mu$ C and +6.6 $\mu$ C, respectively, are separated by 0.20 m. What is the potential energy of this 2-charge system? (k_e = 8.99* 10⁹ N.m²/C²)

An electron and a proton are each released from rest in the same uniform electric field. The electron moves a distance d_electron and the proton moves a distance d_proton as each particle's kinetic energy increases by 1.6 eV. How do d_electron and d_proton compare?

If an electron is accelerated from rest through a potential difference of 300 V, find its approximate speed at the end of this process. (e = 1.6 * 10 ^- ¹⁹ C; m_e = 9.1 *10 ^- ³¹ kg)

An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plates is 5.0 mm and the potential difference across the plates is 20 V, with what velocity does the electron hit the positive plate? (m_e = 9.1 * 10 ^- ³¹ kg, e = 1.6 *10 ^- ¹⁹ C)

A uniform electric field, with a magnitude of 600 N/C, is directed parallel to the positive x axis. If the potential at x = 4.0 m is 1000 V, what is the change in potential energy of a proton as it moves from x = 4.0 m to x = 1.0 m? (q_p = 1.6 *10 ^- ¹⁹ C)

An electron in a cathode ray tube is accelerated through a potential difference of 10 kV. What kinetic energy does the electron gain in the process? (e = 1.6 * 10 ^- ¹⁹C)

An electron (charge -1.6 *10 ^- ¹⁹C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C. How much work is done on the electron as it moves 20 cm?

A proton (+1.6 *10 ^- ¹⁹ C) moves 10 cm on a path in the direction opposite to a uniform electric field of strength 3.0 N/C. How much work is done on the proton by the electrical field?