The combustion of liquefied butane to form carbon dioxide and water vapor occurs according to the reaction below.What is the enthalpy change per mole of CO₂ produced?
2 C₄ H₁₀ (l) + 13O₂ (g) $\rightarrow$ 4 CO₂ (g) +5H₂ O(l) $\Delta$ H =-2707.8 kJ

Question

The combustion of liquefied butane to form carbon dioxide and water vapor occurs according to the reaction below.What is the enthalpy change per mole of CO₂ produced?
2 C₄ H₁₀ (l) + 13O₂ (g)

\rightarrow

4 CO₂ (g) +5H₂ O(l)

\Delta

H =-2707.8 kJ

Quizplus · Accepted Answer

The Answer of The combustion of liquefied butane to form carbon dioxide and water vapor occurs according to the reaction below.What is the enthalpy change per mole of CO₂ produced? 2 C₄ H₁₀ (l) + 13O₂ (g) $\rightarrow$ 4 CO₂ (g) +5H₂ O(l) $\Delta$H =-2707.8 kJ

The Combustion of Liquefied Butane to Form Carbon Dioxide and Water